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Contoh pemecahan soal subnetting

10 Apr

1. Hitunglah jumlah subnet, host persubnet, blok subnet, dan tabel lengkap pada IP 192.168.1.0/27

peny :

192.168.1.0/27 == 11111111.11111111.11111111.11100000 == 255.255.255.224

hitungan 224 diperoleh dari : 2^0+2^1+2^2+2^3+2^4+2^5+2^6+2^7. (hitung angka dari paling kiri)

hitungan 224 diperoleh : 0+0+0+0+0+32+64+126 = 224

Rumus Subnet : 2^x (x=jumlah angka nilai 1 pada bentuk desimal IP)

baca selengkapnya

 
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Posted by on 10 April 2012 in Network

 

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